Forces Star Pass

I already said my brain isn't smart enough, I'm sorry.

If the explanation is only about cells then this question cannot be answered, but if the explanation is about initial position of blocks, question will be answered (maybe).

And if we talk about blocks in one cell, it would be better if we give demo not only 2 blocks but 3 or more blocks in one cell including fixed blocks too.

For example:

 

For a fixed wedge why can't it be passed? even though the metal wedge underneath, should have been hit by a star effect that made it passable (invisible).

So this so-called wedge effect dominates over the star effect?

But if it was reversed or replaced with a movable wedge, the result would be different, since both were hit by the star effect.

And my brain still can't understand it well.

 

@Denis Nazin
I'm trying to understand. What is meant by physical is this?

Spoiler

https://mekoramaforum.com/threads/physical-dimensions-of-mekorama-blocks.635/

and stars are considered to have no physical? (air/wind/void)

And if 2 blocks are in one cell, then there is only one "blok property" occupying that cell?

As for the physical, can one block or a combination of 2 blocks or produce a new block?

 

How about elevated stair? Stairs take up half a cell.

 

The middle stairs is so special to me. How far can L go?

 

[BDAY] Perfect Angel Day
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Spoiler

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Spoiler: Video

 

@935 It is about the position of the Star against the movable Block.
Take a look at the cube in this demo.

If you put the robot (body) on the brick, then the star will be active in all positions.
If you put the robot (body) in the water, then the star will be active if you put it on the grass and win.

The order is: brick<stone<dirt<metal<draggable<water<grass<win

Or try making lots of star shadows. After that remove the stars one by one, then the shadow will be a star, see the order.

 

For the star on the ball it's the same (I guess).
Note the position of the star against the slider.

 

I have to thank you @935 I just realized the sequence has to do with the trigger position for the sensor. I will research it further.

 

@Denis Nazin can you help me? to create an explanatory picture of the sequence.

 

The order is starting from the brick, the direction is from left to right. after that dirt, then stone. if it reaches the top then return from the bottom again, grass, the direction is the same to the right. and continues onwards.

I can't make a good picture. Your explanation with arrows will be easier to understand.
Thank you.

 

It's about positioning the star against the movable block, so the starpass can work.



I'll give an example on the x and y axes.

There are 7 layers. We count from bottom to top. Each layer contains 16 blocks, counting from left to right.

For example, the first layer we give the number 1-16 then the second layer 17-32 and so on until the last layer. Here's the order.

So if I put the robot in that position. The star that can work is in the position of the number after the robot.

For example if I put a star on a brick, the starpass will not work because it is in the number before the robot. whereas if I put a star on the grass then the starpass will work.

 

And for the z-axis the direction is from back to front.

After the numbering reaches the top, then the next number is in front of number 1.

So if i put stars in all areas behind the robot then starpass will not work, and if i put stars in all areas in front of robot then starpass will work.

 

Movable block. B's body is an example. you can replace it with a ball, slider or something else.